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\documentclass{book}%
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\begin{document}
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\title{The Title}
\author{The Author}
\date{The Date}
\maketitle
\tableofcontents
$y=\left( 5x^{3}-4x\right) \left( x^{2}+5x\right) =\allowbreak
5x^{5}+25x^{4}-4x^{3}-20x^{2}$
$\bigskip$
$y=uv\Longrightarrow y'$
\bigskip
\bigskip
\end{document}

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\chapter{Differentialrechnung}
\section{Ableitungsregeln}
\subsection{Produktregel}
\fbox{$y=uv\Longrightarrow y'=u'v+v'u$}
\subsubsection{A1 $ y= \left( {5x^3 - 4x} \right)\left( {x^2 + 5x} \right),\text{ }y' = ?$}
Die vorliegende Funktion ist ein \emph{Produkt aus zwei} Faktoren \emph{u} und \emph{v}, die jeweils von der Variablen \emph{x} abh<62>ngen:
\begin{tabbing}
\tabumg
\>\>$y=\underbrace{\left( {5x^3 - 4x} \right)}_{u}\underbrace{\left( {x^2 + 5x} \right)}_{v}=uv$\\
Somit gilt:\\
\\
Bem. S.R: gliedweise Differenzierung per $y'=n\cdot x^{n-1}$\\
\\
\>\>$u=5x^3-4x,\text{ }v=x^2 + 5x $ und $u'=15x^2-4\text{ }v'=2x+5$\\
\\
Die Produktregel liefert dann die gesuchte Ableitung:\\ \\
\>\>$y'=u'v+v'u=(15x^2 - 4)(x^2 + 5x)$
\end{tabbing}
%http://www.math.montana.edu/frankw/ccp/multiworld/topic.htm#contents

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%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%\begin{appendix}%
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\documentclass{article}
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\input{tcilatex}
\begin{document}
$y=5x^{3}$ Solution: $y^{\prime }=15x^{2}$
\bigskip
$y=5x^{3}-4x$ Solution: $y^{\prime }=15x^{2}-4$
\end{document}